Sodium hydroxide and Aluminium chloride reaction | NaOH + AlCl3

Aqueous aluminium chloride solution reacts with aqueous sodium hydroxide and give results according to the amount of available sodium hydroxide to react with Aluminium chloride. This reaction can be used to identify aluminium ion from other several cations in qualitative analysis. In this tutorial, we will learn how these reactions happen in detail.


aluminium chloride and sodium hydroxide reaction

Slowly adding sodium hydroxide to aluminium chloride solution

If, sodium hydroxide is slowly added to aqueous aluminium chloride solution, a white precipitate of aluminium hydroxide (Al(OH)3) is given. This reaction is not a redox reaction because oxidation numbers of atoms are not changed during the reaction.

AlCl3(aq) + NaOH(aq) → Al(OH)3(s) + NaCl(aq)


Balanced equation can be written as below.

AlCl3(aq) + 3NaOH(aq) → Al(OH)3(s) + 3NaCl(aq)



Adding excess sodium hydroxide to aluminium hydroxide precipitate

If more sodium hydroxide is added to the solution which contains aluminium hydroxide precipitate, precipitate will dissolve and give a sodium aluminate (NaAl(OH)4), a colourless aqueous solution.

Al(OH)3(s) + NaOH(aq) → NaAl(OH)4



Balanced reactions of AlCl3 and NaOH reaction

balanced reactions of AlCl3 + NaOH

Adding solid sodium hydroxide or solid aluminium chloride

  • You can observe the same reaction of solid sodium hydroxide pellets or powder is added to the aqueous aluminium chloride solution. But, keep in mind that adding large amount of sodium hydroxide will not give the observation of white precipitate forming because large amount of hydroxyl ion causes to form sodium aluminate, colourless aqueous solution.
  • As well as, you can add solid state aluminium chloride to aqueous sodium hydroxide solution. Most times, it will not give the white precipitate because, there are excess hydroxyl ion to form sodium aluminate.


Which metal cation can be identified from this reaction

  • All alkali metal cations except Lithium can be identified because those alkali metal cations do not make precipitates with NaOH. Lithium form a white precipitate, but not soluble in excess NaOH as Aluminium cation does.
  • Because hydroxides of magnesium and calcium is not soluble in excess NaOH, magnesium and calcium also can be identified from aluminium +3 ion.
  • Zinc +2 cation cannot be identified from aluminium +3 because zinc hydroxide is a white precipitate and soluble in excess NaOH.

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