Acetylene gas is an alkyne and ethanol is an alcohol compound. Acetylene has two car atoms in that molecule and contains a triple bond. Ethanol also has two cabon atoms and -OH group in it's molecule.
Acetylene / ethyne / C2H2
Ethanaol / ethyl alcohol / CH3CH2OH
In this question we are going to prepare ethanol from two methods.
First, acetylene is converted into ethene ( CH2 = CH2 ) using hydrogen gas and Lindlar catalyst. Ethene is an an alkene compound.
Alkynes are converted to alkenes by in the presence of hydrogen gas and lindlar catalyst.
lindlar reagent contains CaCO3, Pd and various forms of sulfur and lead
Then ethanol is prepared from the reaction of ethene with
dilute sulfuric acid.
Acetylene reacts with HgSO4 and dilute H2SO4. It gives ethanal ( CH3CHO ). Ethanal is a aldehyde compound.
Ethanl is reduced to ethanol by LiAlH4, ether. CH3CHO reacts with LiAlH4, ether, H2O to give ethanol.
NaBH4, Na / C2H5OH, H2 / Ni also can be used to reduce ethanl to ethanol.
We can obtain acetylene gas from calcium carbide(CaC2). CaC2 react with water and
Acetylene is an alkyne compound and ethanol is an alcohol. Both acetylene and ethanol show acidic characteristics with Na and emits H2. But none of them react with NaOH. Acetylene gives a red precipitate with ammoniacal copper chloride and white precipitate with ammoniacal silver nitrate. But alcohol does not give such precipitates with those solutions.
It's easy. Only you have to do is treating hydrogen gas with Pt catalyst with Lindlar catalyst. This will give ethylene. Tripple bond is converted to double bond by addition of two of hydrogen atoms.